+0  
 
0
624
1
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How do I solve 

$${\frac{{\mathtt{6}}}{{{tg}{\left({\mathtt{x}}\right)}}^{\,{\mathtt{2}}}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{x}}\right)}}^{\,{\mathtt{2}}} = {\mathtt{1.5}}$$

Guest Jul 10, 2015

Best Answer 

 #1
avatar+27251 
+10

I assume tg(x) is tan(x) = sin(x)/cos(x).

Trig equation

.

Alan  Jul 11, 2015
 #1
avatar+27251 
+10
Best Answer

I assume tg(x) is tan(x) = sin(x)/cos(x).

Trig equation

.

Alan  Jul 11, 2015

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