how do i solve a problem with a negative fraction exponent?

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Guest Feb 22, 2015

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Best Answer

$$\\7x^{1/3}=7*\sqrt[3]{x}\\\\
6x^{-4}=\frac{6}{x^{+4}}\\\\
12x^{-3/2}=\frac{12}{x^{+3/2}}=\frac{12}{x^{1+1/2}}=\frac{12}{x\sqrt{x}}$$

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Melody Feb 22, 2015

Melody · Answer 1 · 2015-02-22T12:49:33

$$\\7x^{1/3}=7*\sqrt[3]{x}\\\\
6x^{-4}=\frac{6}{x^{+4}}\\\\
12x^{-3/2}=\frac{12}{x^{+3/2}}=\frac{12}{x^{1+1/2}}=\frac{12}{x\sqrt{x}}$$

Here are more examples