How do I solve a side-side-angle triangle, using analysis? I've already attempted using the law of Sines, I just get a syntax error in my calculator (Yes, it is in degree mode and working proper)
+23254 The parts of SSA may not determine a triangle.
For instance, if you are given an angle (A), the side adjacent to the angle (S1), and the side opposite to the angle (S2), S2 must be at least as large as S1·sin(A).
if A = 30°, S1 = 12, and S2 = 5, there won't be a triangle, S2 is too short!
S1·sin(A) = 12·sin(30) = 6 ---> means that there won't be a triangle because S2 is too short (it's only 5).
If S2 < S1·sin(A) ---> there won't be a triangle.
If S2 = S1·sin(A) ---> the triangle is a right triangle.
If S2 > S1·sin(A) and S2 < S1 ---> there will be two possible triangles.
If S2 > S1·sin(A) and S2 ≥ S1 ---> there will be one triangle.
+130516
What probably has happpened is that you actually don't have a triangle.....that's why your calcualtor is "malfunctioning"......this is always a possibility in an SSA problem.....we could have one, two, or no triangles....!!!
I'm not looking at the situation.....but the side opposite the given angle is probably not long enough to "complete" a triangle......in effect.....we have a "swinging" gate
Post the problem if you want us to look at it in more depth....!!!!
+23254 The parts of SSA may not determine a triangle.
For instance, if you are given an angle (A), the side adjacent to the angle (S1), and the side opposite to the angle (S2), S2 must be at least as large as S1·sin(A).
if A = 30°, S1 = 12, and S2 = 5, there won't be a triangle, S2 is too short!
S1·sin(A) = 12·sin(30) = 6 ---> means that there won't be a triangle because S2 is too short (it's only 5).
If S2 < S1·sin(A) ---> there won't be a triangle.
If S2 = S1·sin(A) ---> the triangle is a right triangle.
If S2 > S1·sin(A) and S2 < S1 ---> there will be two possible triangles.
If S2 > S1·sin(A) and S2 ≥ S1 ---> there will be one triangle.
