How do I solve for n in:

How do I solve for n in: 0.25 = 0.5^n

$$\begin{array}{rcl}
0.25 & = & 0.5^n\\\\
\dfrac{1}{4} &=& \left(\dfrac{1}{2} \right)^n\\\\
\dfrac{1}{2^2} &=& \dfrac{1}{2^n} \\\\
2^2 &=& 2^n \\
2&=& n
\end{array}$$

$$\boxed{n= 2}$$