How do I solve for x in 5(10 exponent x+1)=12

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Guest Mar 18, 2015

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Best Answer

5·10^x+1 = 12

Divide by 5: 10^x+1 = 2.4

Take the log of both sides: log(10^x+1) = log(2.4) ---> (x+1)log(10) = log(2.4)

Since log(10) = 1 and log(2.4) = 0.3802 (approx) ---> (x+1)(1) = 0.3802

---> x + 1 = 0.3802 ---> x = -0.6198 (approx)

geno3141 Mar 18, 2015

geno3141 · Answer 1 · 2015-03-18T06:01:52

5·10^x+1 = 12

Divide by 5: 10^x+1 = 2.4

Take the log of both sides: log(10^x+1) = log(2.4) ---> (x+1)log(10) = log(2.4)

Since log(10) = 1 and log(2.4) = 0.3802 (approx) ---> (x+1)(1) = 0.3802

---> x + 1 = 0.3802 ---> x = -0.6198 (approx)