How do I solve for x with the problem 8 less than equal to 16^(7x+2)

I used the < sign in my reply above.  I should, of course, have used the ≤ sign!

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This can be written as 2³<2^{4(7x + 2)} so that we must have 3 < 4(7x + 2)  

or 3 < 28x + 8 or -5 < 28x or -5/28 < x   or -0.1786... < x

see image below:

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