how do I solve this question? [(-2)^3+2/3*6]^5

First, do the exponents:

(-2)^3 = (-2*-2*-2) = -8.

 

Now, we have 2 divided by 3 or 2/3 times 6 = 2/3*6  = 12/3 = 4.

 

Add -8 and 4 --> -8 + 4 = -4.

 

Now, (-4)^5 = (-4*-4*-4*-4*-4) = ?