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How do I solve a system of equations of 2x-3y=40 over x+5y=7.

 Feb 28, 2020
 #1
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how do you solve 6x+3y=14 and 5x-2y=8.

 Feb 28, 2020
 #2
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I assume you mean:

\(2x-3y=40\)  (1)

\(x+5y=7\) (2)

 

Now let's multiply (2) with -2 

\(2x-3y=40\)

\(-2x-10y=-14\) 

Add these two equations

\(-13y=26\)

\(y=-2\)

Now to find x you just substitute  the value of y in either of the two equations

\(x+5y=7 ,x+5(-2)=7, x=7+10=17\)

 

So,

x=17

y=-2

 Feb 28, 2020

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