Two interior angles of a triangle measure 15 degrees and 30 degrees. The perimeter of the triangle is \(\sqrt {10}+\sqrt {20} + \sqrt {30}\).The area of the triangle may be written in the form \(a+b\sqrt{c}\) for integers a, b, and c such that c is square-free. Find abc.
+120 Assume that one of the perimeters as your base such as (sqrt 10, sqrt 20 sqrt 30) now using the height formula (on google) calculate the height, multiple the base, and height divide it by 2 is your answer.
