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Two interior angles of a triangle measure 15 degrees and 30 degrees. The perimeter of the triangle is \(\sqrt {10}+\sqrt {20} + \sqrt {30}\).The area of the triangle may be written in the form \(a+b\sqrt{c}\) for integers a, b, and c such that c is square-free. Find abc.

 Jul 29, 2023
 #1
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Assume that one of the perimeters as your base such as (sqrt 10, sqrt 20 sqrt 30) now using the height formula (on google) calculate the height, multiple the base, and height divide it by 2 is your answer. 

 Jul 29, 2023
 #2
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Thats a way to think about it, but its not a special triangle so that wouldnt work. (I dont think at least). Ive tried spliting the triangle into 2 smaller ones then using 30-60-90 triangles to solve for the height but idk if that will work.

Guest Jul 29, 2023
 #3
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What a d*mb*ss a ops hw cheater!

Guest Jul 30, 2023

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