like n/12—do i just divide? its not in a fraction problem, the rest of the problem is entirely whole numbers,
e.g.: -6(-8+5k)-4=19+n/4. (this is not the real problem) would i just divide at the end? if so, how do i divide with n??
+118723 I just realised that you have an n and a k in the same equation so I won't be able to solve that one anyway.
How about I make up one of my own.
$$\frac{2x}{3}-\frac{5}{6}=\frac{5}{2}$\\
The lowest common denominator is 6 so multiply both sides by 6\\
6\times\left(\frac{2x}{3}-\frac{5}{6}\right)=6\times{\frac{5}{2}}\\\\
\frac{6\times 2x}{3}-\frac{6 \times 5}{6}=\frac{6 \times 5}{2}}\\\\
\frac{2\times 2x}{1}-\frac{1 \times 5}{1}=\frac{3\times 5}{1}}\\\\
4x-5=15\\
4x=20\\
x=5\\$$
Of course it really depends on the exact problems but this is a method that I use a lot of the time. 
+118723 I just realised that you have an n and a k in the same equation so I won't be able to solve that one anyway.
How about I make up one of my own.
$$\frac{2x}{3}-\frac{5}{6}=\frac{5}{2}$\\
The lowest common denominator is 6 so multiply both sides by 6\\
6\times\left(\frac{2x}{3}-\frac{5}{6}\right)=6\times{\frac{5}{2}}\\\\
\frac{6\times 2x}{3}-\frac{6 \times 5}{6}=\frac{6 \times 5}{2}}\\\\
\frac{2\times 2x}{1}-\frac{1 \times 5}{1}=\frac{3\times 5}{1}}\\\\
4x-5=15\\
4x=20\\
x=5\\$$
Of course it really depends on the exact problems but this is a method that I use a lot of the time.
