+118677 How do you do this:
x^-3/2
\(\frac{x^{-3}}{2}=\frac{1*x^{-3}}{2}=\frac{1}{2x^{+3}}=\frac{1}{2x^{3}}\\~\\ \text{or maybe you mean}\\~\\ x^{-3/2}=1*x^{-3/2}=\frac{1}{x^{+3/2}}=\frac{1}{x^{3/2}}\\~\\ \text{can also be written as}\\ \frac{1}{x^{3/2}}=\frac{1}{(\sqrt x)^3}=\frac{1}{\sqrt{x^3}}\)
