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# How do you expand a log function?

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How do you expand a log function?

Guest Nov 23, 2014

#1
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If  you mean a series expansion of something like ln(1 + x) then you can use a Taylor series to get:

$$ln(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+...$$

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Alan  Nov 24, 2014
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#1
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$$ln(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+...$$