How do you expand a log function?

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Guest Nov 23, 2014

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Best Answer

If you mean a series expansion of something like ln(1 + x) then you can use a Taylor series to get:

$ln(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+...$

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Alan Nov 24, 2014

Alan · Answer 1 · 2014-11-24T08:30:05

If you mean a series expansion of something like ln(1 + x) then you can use a Taylor series to get:

$ln(1+x)=x-\frac{x^2}{2}+\frac{x^3}{3}-\frac{x^4}{4}+...$

.