+0  
 
0
915
1
avatar+8 

How do you find out what sin^-1(0,37) is?

When I do it it with 'asin' is says "Too many arguments"

 Jun 27, 2015

Best Answer 

 #1
avatar+33616 
+10

Use asin (press 2nd then asin on the calculator on the home page here):

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.37}}\right)} = {\mathtt{21.715\: \!617\: \!283\: \!264^{\circ}}}$$

.

 Jun 27, 2015
 #1
avatar+33616 
+10
Best Answer

Use asin (press 2nd then asin on the calculator on the home page here):

 

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.37}}\right)} = {\mathtt{21.715\: \!617\: \!283\: \!264^{\circ}}}$$

.

Alan Jun 27, 2015

4 Online Users

avatar
avatar
avatar