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How do you find the average of 20, 37,19,43,26,29

 Mar 15, 2015

Best Answer 

 #3
avatar+129852 
+5

Gotta' be careful here, gibsonj338

Your first answer is correct.....29 is the average

However, your other two answers are not averages......the second answer is the median .....it represents the "middle" value of an ordered data set

The third answer represents the mode......the number that appears most often in a data set....here, there is no mode, since no value appears more than once....

 

  

 Mar 16, 2015
 #1
avatar+893 
+5

Add them up and divide the result by 6.

 Mar 15, 2015
 #2
avatar+1904 
+5

20, 37, 19, 43, 26, 29

 

There are three ways to find the average of these numbers

 

1.  Add up all the numbers and divide by the number of numbers.

 

$${\mathtt{20}}{\mathtt{\,\small\textbf+\,}}{\mathtt{37}}{\mathtt{\,\small\textbf+\,}}{\mathtt{19}}{\mathtt{\,\small\textbf+\,}}{\mathtt{43}}{\mathtt{\,\small\textbf+\,}}{\mathtt{26}}{\mathtt{\,\small\textbf+\,}}{\mathtt{29}} = {\mathtt{174}}$$

 $${\frac{{\mathtt{174}}}{{\mathtt{6}}}} = {\mathtt{29}}$$

 

2.  Put the numbers in order from lowest to highest and the number in the middle is the average.  If there are two numbers in the middle, add both numbers and then divide by two to get your average.

 

19, 20, 26, 29, 37, 43

 

$${\mathtt{26}}{\mathtt{\,\small\textbf+\,}}{\mathtt{29}} = {\mathtt{55}}$$

 

$${\frac{{\mathtt{55}}}{{\mathtt{2}}}} = {\mathtt{27.5}}$$

 

3.  Look at the numbers and whatever number you have the most of is your average.

Since no numbers repeat, this option will not work.

 Mar 15, 2015
 #3
avatar+129852 
+5
Best Answer

Gotta' be careful here, gibsonj338

Your first answer is correct.....29 is the average

However, your other two answers are not averages......the second answer is the median .....it represents the "middle" value of an ordered data set

The third answer represents the mode......the number that appears most often in a data set....here, there is no mode, since no value appears more than once....

 

  

CPhill Mar 16, 2015

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