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How do you find the ordered pair of the vertex of the parabola y=-3x^2-6x+4

 Mar 25, 2015

Best Answer 

 #1
avatar+128732 
+5

y=-3x^2-6x+4

Letting b = -6  and a = -3.....the x coordinate of the vertex is given by

-b/[2a]  =  -(-6)/ [2(-3)]  = 6/-6  = -1

And to find y, put this value back into the function

y = -3(-1)^2 -6(-1) + 4  =  -3 + 6 + 4  = 7

Here's the graph of this.....https://www.desmos.com/calculator/82uujkwl4x

 

  

 Mar 25, 2015
 #1
avatar+128732 
+5
Best Answer

y=-3x^2-6x+4

Letting b = -6  and a = -3.....the x coordinate of the vertex is given by

-b/[2a]  =  -(-6)/ [2(-3)]  = 6/-6  = -1

And to find y, put this value back into the function

y = -3(-1)^2 -6(-1) + 4  =  -3 + 6 + 4  = 7

Here's the graph of this.....https://www.desmos.com/calculator/82uujkwl4x

 

  

CPhill Mar 25, 2015

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