How do you find the ordered pair of the vertex of the parabola y=-3x^2-6x+4
y=-3x^2-6x+4
Letting b = -6 and a = -3.....the x coordinate of the vertex is given by
-b/[2a] = -(-6)/ [2(-3)] = 6/-6 = -1
And to find y, put this value back into the function
y = -3(-1)^2 -6(-1) + 4 = -3 + 6 + 4 = 7
Here's the graph of this.....https://www.desmos.com/calculator/82uujkwl4x
y=-3x^2-6x+4
Letting b = -6 and a = -3.....the x coordinate of the vertex is given by
-b/[2a] = -(-6)/ [2(-3)] = 6/-6 = -1
And to find y, put this value back into the function
y = -3(-1)^2 -6(-1) + 4 = -3 + 6 + 4 = 7
Here's the graph of this.....https://www.desmos.com/calculator/82uujkwl4x