How do you find the point of intersection using these to equations?
x=-2y-3
4y-x=9
x=-2y-3
4y-x=9
Notice that we can substitute the first thing into the second....this gives
4x - (-2y - 3) = 9 simplify
6y + 3 = 9 subtract 3 from both sides
6y = 6 divide both sides by 6
y = 1 and subtituting this back into x = -2y - 3 , we find that x = -2(1) - 3 = -5
So our answer is x = -5 and y =1
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$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x, y}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{x}}={\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{x}}={\mathtt{9}}\end{array}\right)} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{5}}\\
{\mathtt{y}} = {\mathtt{1}}\\
\end{array} \right\}$$
x=-2y-3
4y-x=9
Notice that we can substitute the first thing into the second....this gives
4x - (-2y - 3) = 9 simplify
6y + 3 = 9 subtract 3 from both sides
6y = 6 divide both sides by 6
y = 1 and subtituting this back into x = -2y - 3 , we find that x = -2(1) - 3 = -5
So our answer is x = -5 and y =1
![]()
Wow.....thanks h7....I didn't even know you could do that on this calculator!!....did you figure that out just fooling around with it ????
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No....I just answered.....I don't know what this calc can do......now you know!
$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x, y}}}}}{{solve}}{\left(\begin{array}{l}{\mathtt{x}}={\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{3}}\\
{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{y}}{\mathtt{\,-\,}}{\mathtt{x}}={\mathtt{9}}\end{array}\right)} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{5}}\\
{\mathtt{y}} = {\mathtt{1}}\\
\end{array} \right\}$$!