How do you get rid of an exponent in an equation?

Question

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1236

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Guest Apr 24, 2015

+118723

+5

Best Answer

What like

$5^x=7\\ log5^x=log7\\ xlog5=log7\\ x=log7 \div log 5\\$

${\frac{{log}_{10}\left({\mathtt{7}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} = {\mathtt{1.209\: \!061\: \!955\: \!122\: \!167\: \!3}}$

Melody Apr 24, 2015

Melody · Answer 1 · 2015-04-24T05:58:10

What like

$5^x=7\\ log5^x=log7\\ xlog5=log7\\ x=log7 \div log 5\\$

${\frac{{log}_{10}\left({\mathtt{7}}\right)}{{log}_{10}\left({\mathtt{5}}\right)}} = {\mathtt{1.209\: \!061\: \!955\: \!122\: \!167\: \!3}}$

Guest · Answer 2 · 2015-04-24T04:30:34

^^^Okay, if you're going to be a troll go away. I'm looking for an actual answer to the question. What actually are you doing with your life????