How do you rearrange the equation for t??

h = 38(1 - e^-0.049t)

 

Divide both sides by 38

h/38 = 1 - e^-0.049t

 

Add e^-0.049t to both sides

h/38 + e^-0.049t = 1

 

Subtract h/38 from both sides

e^-0.049t = 1 - h/38

 

Take natural logs of both sides

ln(e^-0.049t) = ln(1 - h/38)

-0.049t = ln(1 - h/38)   because ln(e^a) = a

 

Divide both sides by -0.049

t = -(1/0.049)*ln(1 - h/38)