how do you simplify 6 times the cubed root of 250 y to the 7th?

how do you simplify 6 times the cubed root of 250 y to the 7th

is this your intended question?

 

$$\\6*\sqrt[3]{250}*y^7\\\\
=6*\sqrt[3]{125*2}*y^7\\\\
=6*5\sqrt[3]{2}*y^7\\\\
=30y^7\sqrt[3]{2}\\\\$$

I have difficulty with LaTex but I believe that it reduces to 30y^2 times the cube root of 2y.

Consider:

250 is 2(5^3); the cube root of 5^3 is 5 (moved outside the radical)

y^7 is (y^3)(y^3)(y); the cube root of y^3 is y. twice so resuts in y^2 outside the radical.

6 (5)(y^2) time cube root of 2y.