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how do you solve 47-5*11 over -12+4^2? frown

 Nov 4, 2015
 #1
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 how do you solve 47-5*11 over -12+4^2?                                                                                 Simplify the following:
(47-5×11)/(-12+4^2)

4^2 = 16:
(47-5×11)/(-12+16)

-12+16 = 4:
(47-5×11)/4

-5×11  =  -55:
(47+-55)/4

47-55  =  -(55-47):
-(55-47)/4

| 4 | 15
| 5 | 5
- | 4 | 7
| 0 | 8:
(-8)/4

The gcd of -8 and 4 is 4, so (-8)/4 = (4 (-2))/(4×1) = 4/4×-2 = -2:
Answer: | 
| -2

 Nov 5, 2015

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