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how do you solve a system of linear equations

3x+4y=17

-4x-3y=-18

 Nov 11, 2014

Best Answer 

 #1
avatar+130511 
+5

3x+4y=17

-4x-3y=-18

Multiply the top equation by 4 and the bottom equation by 3.....this gives......

12x + 16y =  68

-12x - 9y  = -54        add these together

 

7y  =      14        divide by 7 on both sides

y = 2         

And we can use 3x + 4y = 17 to find x

3x + 4(2) = 17

3x + 8     = 17    subtract 8 from both sides

3x  = 9               divide by 3 on both sides

x = 3

So..our solutions are   x = 3 and y  = 2

 

 Nov 11, 2014
 #1
avatar+130511 
+5
Best Answer

3x+4y=17

-4x-3y=-18

Multiply the top equation by 4 and the bottom equation by 3.....this gives......

12x + 16y =  68

-12x - 9y  = -54        add these together

 

7y  =      14        divide by 7 on both sides

y = 2         

And we can use 3x + 4y = 17 to find x

3x + 4(2) = 17

3x + 8     = 17    subtract 8 from both sides

3x  = 9               divide by 3 on both sides

x = 3

So..our solutions are   x = 3 and y  = 2

 

CPhill Nov 11, 2014

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