How do you solve for x in this case? 1.06^x=2

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Guest Feb 5, 2015

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Best Answer

Anon's answer is correct. :)

Here is another answer :) they will give the same answer.

$$\\1.06^x=2\\\\
log(1.06^x)=log2\\\\
xlog1.06=log2\\\\
x=\frac{log2}{log1.06}\\\\$$

Melody Feb 5, 2015

Melody · Answer 1 · 2015-02-05T11:05:28

Anon's answer is correct. :)

Here is another answer :) they will give the same answer.

$$\\1.06^x=2\\\\
log(1.06^x)=log2\\\\
xlog1.06=log2\\\\
x=\frac{log2}{log1.06}\\\\$$

Guest · Answer 2 · 2015-02-05T05:44:15

divide by 1.06 (both sides) so it would look like 1.06x/1.06=2/1.06 which would give you 1.88679

Guest · Answer 3 · 2015-02-05T08:56:00

$${{log}}_{{\mathtt{1.06}}}{\left({\mathtt{2}}\right)}$$

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