log5^(2x+1)=log8
Assuming that both logs are to base 10, we can just solve this :
(2x + 1) * log 5 = log 8 divide both sides by log 5
2x + 1 = log 8 / log 5 subtract 1 from both sides
2x = log 8 / log 5 - 1 divide both sides by 2
x = [ log 8 / log 5 - 1] / 2 ≈ 0.146
