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how do you solve log5^(2x+1)=log8 

Guest Apr 4, 2017
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log5^(2x+1)=log8 

 

Assuming  that  both logs are to base 10, we can just solve this :

 

(2x + 1) * log 5  =   log 8        divide both sides by log 5

 

2x + 1   = log 8 / log 5        subtract 1 from both sides

 

2x  =   log 8 / log 5   - 1      divide both sides by 2

 

x  =   [ log 8 / log 5  -  1]  /   2  ≈    0.146

 

 

cool cool cool

CPhill  Apr 4, 2017

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