+0  
 
0
349
1
avatar

how do you solve log5^(2x+1)=log8 

Guest Apr 4, 2017
 #1
avatar+89702 
+1

log5^(2x+1)=log8 

 

Assuming  that  both logs are to base 10, we can just solve this :

 

(2x + 1) * log 5  =   log 8        divide both sides by log 5

 

2x + 1   = log 8 / log 5        subtract 1 from both sides

 

2x  =   log 8 / log 5   - 1      divide both sides by 2

 

x  =   [ log 8 / log 5  -  1]  /   2  ≈    0.146

 

 

cool cool cool

CPhill  Apr 4, 2017

12 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.