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0=6x^2-18x

 Jan 11, 2015

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 #2
avatar+118724 
+5

You make it look kinda hard anon ;)

 

$$\\0=6x^2-18x\\\\
0=6x(x-3)\\\\
x=0\;\;or\;\;x-3=0\\\\
x=0\;\;or\;\;x=3\\\\$$

 Jan 11, 2015
 #1
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+5

$${\mathtt{0}} = {\mathtt{\,-\,}}{\frac{{\mathtt{P}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{or}}{\mathtt{\,-\,}}{\sqrt{{\left({\frac{{\mathtt{p}}}{{\mathtt{2}}}}\right)}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{q}}}}$$   where p=b and q=c when a=1 in the general form of a quadratic equation 0=ax^2+bx+c. So first divide the right part of your equation so that the constant in front of x^2 equals 1 and then apply the given formula above.

 Jan 11, 2015
 #2
avatar+118724 
+5
Best Answer

You make it look kinda hard anon ;)

 

$$\\0=6x^2-18x\\\\
0=6x(x-3)\\\\
x=0\;\;or\;\;x-3=0\\\\
x=0\;\;or\;\;x=3\\\\$$

Melody Jan 11, 2015

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