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$$4logx^{3}-3logx^{2}=12$$

 Sep 4, 2014

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 #1
avatar+118651 
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$$\\4logx^{3}-3logx^{2}=12\\
log(x^3)^4-log(x^{2})^3=12\\
log(x^{12})-log(x^6)=12\\
log(\frac{x^{12}}{x^6})=12\\
log\;x^{6}=12\\
6log\;x=12\\
log\;x=2\\
10^{log\;x}=10^2\\
x=100$$

.
 Sep 6, 2014
 #1
avatar+118651 
+5
Best Answer

 

$$\\4logx^{3}-3logx^{2}=12\\
log(x^3)^4-log(x^{2})^3=12\\
log(x^{12})-log(x^6)=12\\
log(\frac{x^{12}}{x^6})=12\\
log\;x^{6}=12\\
6log\;x=12\\
log\;x=2\\
10^{log\;x}=10^2\\
x=100$$

Melody Sep 6, 2014

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