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How do you solve (x-6)^2=7

 Jan 25, 2015

Best Answer 

 #1
avatar
+5

(x-6)^2=7

x-6=±sqrt(7)

x=6±sqrt(7)

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x}}}}}{{solve}}{\left(\begin{array}{l}{\sqrt{{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}\right)}^{{\mathtt{2}}}}}={\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}={\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}={\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}={\mathtt{6}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\end{array}\right)}$$

 Jan 25, 2015
 #1
avatar
+5
Best Answer

(x-6)^2=7

x-6=±sqrt(7)

x=6±sqrt(7)

$$\underset{\,\,\,\,{\textcolor[rgb]{0.66,0.66,0.66}{\rightarrow {\mathtt{x}}}}}{{solve}}{\left(\begin{array}{l}{\sqrt{{\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}\right)}^{{\mathtt{2}}}}}={\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}={\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}={\mathtt{6}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{7}}}}\\
{\mathtt{x}}={\mathtt{6}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{7}}}}\end{array}\right)}$$

Guest Jan 25, 2015
 #2
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Well presented,  Anonymous.....why don't you become a member???....then, you wouldn't be "Anonymous" anymore !!!

 

 Jan 26, 2015

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