On the web2.0calc calculator put it in as: log(16, 3)
The result should give you: $${{log}}_{{\mathtt{3}}}{\left({\mathtt{16}}\right)}$$
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The answer above is correct as well.
On the web2.0calc calculator put it in as: log(16, 3)
The result should give you: $${{log}}_{{\mathtt{3}}}{\left({\mathtt{16}}\right)}$$
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The answer above is correct as well.