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how do you use this formula (r=(1+APR/365)^365-1)

 May 21, 2014

Best Answer 

 #1
avatar+118723 
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Say the nominal interest rate is 12%pa but it is compounded daily

Then the real interest rate will be a little higher.

r=  $${\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{0.12}}}{{\mathtt{365}}}}\right)}^{{\mathtt{365}}}{\mathtt{\,-\,}}{\mathtt{1}} = {\mathtt{0.127\: \!474\: \!615\: \!638\: \!402\: \!6}}$$

So the real interest rate is 12.7%

Obviously if you are comparing interest rates you want to compare the real ones.

 May 21, 2014
 #1
avatar+118723 
+5
Best Answer

Say the nominal interest rate is 12%pa but it is compounded daily

Then the real interest rate will be a little higher.

r=  $${\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{0.12}}}{{\mathtt{365}}}}\right)}^{{\mathtt{365}}}{\mathtt{\,-\,}}{\mathtt{1}} = {\mathtt{0.127\: \!474\: \!615\: \!638\: \!402\: \!6}}$$

So the real interest rate is 12.7%

Obviously if you are comparing interest rates you want to compare the real ones.

Melody May 21, 2014

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