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how do you work out$${\left({\frac{{\mathtt{4}}}{{\mathtt{9}}}}\right)}^{{\mathtt{1.5}}}$$? I know the answers $${\frac{{\mathtt{8}}}{{\mathtt{27}}}}$$ but not why?

 Aug 26, 2015

Best Answer 

 #1
avatar+118608 
+10

Why don't you join up?  You are asking some good questions today :)

 

$$\\\left(\frac{4}{9}\right)^{1.5}\\\\
=\left(\frac{4}{9}\right)^{3/2}\\\\
=\left(\left(\frac{4}{9}\right)^{1/2}\right)^3\\\\
=\left(\frac{\sqrt4}{\sqrt9}\right)^3\\\\
=\left(\frac{2}{3}\right)^3\\\\
=\frac{2^3}{3^3}\\\\
=\frac{8}{27}\\\\$$

 Aug 26, 2015
 #1
avatar+118608 
+10
Best Answer

Why don't you join up?  You are asking some good questions today :)

 

$$\\\left(\frac{4}{9}\right)^{1.5}\\\\
=\left(\frac{4}{9}\right)^{3/2}\\\\
=\left(\left(\frac{4}{9}\right)^{1/2}\right)^3\\\\
=\left(\frac{\sqrt4}{\sqrt9}\right)^3\\\\
=\left(\frac{2}{3}\right)^3\\\\
=\frac{2^3}{3^3}\\\\
=\frac{8}{27}\\\\$$

Melody Aug 26, 2015
 #2
avatar+128578 
+5

Remember that 1.5 = 3/2.....so we have

(4/9)3/2  = [(4/9)1/2]3 =  [√(4/9)]3   = (2/3)3 = 8/27

 

 

 Aug 26, 2015

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