How does (2x+7)^2-7^2 result in 4x^2+28x+49-49 ?

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How does (2x+7)^2-7^2 result in 4x^2+28x+49-49 ?

Guest Nov 22, 2015

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Best Answer

+130555

+10

(2x + 7)^2 - 49 = (2x + 7) (2x + 7 ) - 49 =

2x + 7

2x + 7

--------

14x + 49

4x^2 + 14x

---------------------

4x^2 + 28x + 49

And subtracting 49 from this gives us 4x^2 + 28x + 49 - 49

CPhill Nov 22, 2015

1⁺⁰ Answers

+130555

+10

Best Answer

(2x + 7)^2 - 49 = (2x + 7) (2x + 7 ) - 49 =

2x + 7

2x + 7

--------

14x + 49

4x^2 + 14x

---------------------

4x^2 + 28x + 49

And subtracting 49 from this gives us 4x^2 + 28x + 49 - 49

CPhill Nov 22, 2015

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