how dose (3)^2*-3^5/3^4 = -27

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Guest Feb 26, 2015

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Best Answer

$\\(3)^2*-3^5/3^4\\\\ =\frac{(3)^2*-3^5}{3^4}\\\\ =\frac{9*-3^5}{3^4}\\\\ =9*-1*3^{5-4}\\\\ =9*-1*3\\\\ =-27\\\\$

Melody Feb 26, 2015

Melody · Answer 1 · 2015-02-26T01:49:38

$\\(3)^2*-3^5/3^4\\\\ =\frac{(3)^2*-3^5}{3^4}\\\\ =\frac{9*-3^5}{3^4}\\\\ =9*-1*3^{5-4}\\\\ =9*-1*3\\\\ =-27\\\\$

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