how dose (3)^2*-3^5/3^4 = -27

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Guest Feb 26, 2015

+118609

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Best Answer

$$\\(3)^2*-3^5/3^4\\\\
=\frac{(3)^2*-3^5}{3^4}\\\\
=\frac{9*-3^5}{3^4}\\\\
=9*-1*3^{5-4}\\\\
=9*-1*3\\\\
=-27\\\\$$

Melody Feb 26, 2015

Melody · Answer 1 · 2015-02-26T01:49:38

$$\\(3)^2*-3^5/3^4\\\\
=\frac{(3)^2*-3^5}{3^4}\\\\
=\frac{9*-3^5}{3^4}\\\\
=9*-1*3^{5-4}\\\\
=9*-1*3\\\\
=-27\\\\$$

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