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how dose (3)^2*-3^5/3^4 = -27

Guest Feb 26, 2015

Best Answer 

 #1
avatar+93683 
+5

$$\\(3)^2*-3^5/3^4\\\\
=\frac{(3)^2*-3^5}{3^4}\\\\
=\frac{9*-3^5}{3^4}\\\\
=9*-1*3^{5-4}\\\\
=9*-1*3\\\\
=-27\\\\$$

Melody  Feb 26, 2015
 #1
avatar+93683 
+5
Best Answer

$$\\(3)^2*-3^5/3^4\\\\
=\frac{(3)^2*-3^5}{3^4}\\\\
=\frac{9*-3^5}{3^4}\\\\
=9*-1*3^{5-4}\\\\
=9*-1*3\\\\
=-27\\\\$$

Melody  Feb 26, 2015

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