how is3^3+4(21(7+2*3)) = 59?
33 + 4( 21( 7 + 2·3 ) )
= 27 + 4( 21( 7 + 2·3 ) )
= 27 + 4( 21( 7 + 6 ) )
= 27 + 4( 21( 13 ) )
= 27 + 4( 273 )
= 27 + 1092
= 1119
Are you sure that you copied the problem correctly?
I mean't 3^3+4(21-(7+2*3))
Sorry, my bad
Plus, you helped me break down my real problem and now understand it better.
So thanks geno3141.
\(3^3 +4(21 - (7+2*3) =59\)
\(27+ 4(21-(7+6) =59\)
\(27+4(21-13)=59 \)
\(27+32 =59 \)
\(59=59\)\(\)
My bad didn't see your comment. I guess you can still double check.
+23251 
