How manu atoms are in 4 mol Zn

Hello Electric Pavlov,

\(4mol\times6.022{\color{red}1}\times 10^{23}atoms/mol\)

\(=24.0884\times10^{23}atoms\)      !

Each mole has Avagadro's number of atoms in it:  6.022 x 10^23     you have 4 moles

 4x 6.0223 =24.088 x 10^23  atoms

Hello Asinus   ... I just rounded a bit....BUT:

Avagadro's number = 6.022140857 × 10^23.

   so   4 x 6.022140857 x 10^23  = 24.088563428 x 10^23 atoms        LOL !!!