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How many cosmological decades are in one Earth year, and how many cosmological decades are in 2015 Earth years? (if possible to calculate).

 Dec 31, 2014

Best Answer 

 #13
avatar+118673 
+8

Happy New Year DavidQD

Happy New year CPhill

and

Happy New Year NotTheBestMathMaster   :)

 

 

 

 

 


  

 

        

 Jan 1, 2015
 #1
avatar+11912 
+5

its New Year anon, just enjoy,who cares for the "decades"!ha!

 

 Dec 31, 2014
 #2
avatar+360 
+5

Next answer is more revised than last..

 Dec 31, 2014
 #3
avatar+360 
+5

Basically, each cosmological decade is ten times the length of all the previous time put together.

The word "decade" does not always mean ten years, it can also mean a set or series of ten.

The universe is now a little over ten to the tenth power years old (ten billion, or 1 with ten zeros after it), so we are living in the tenth cosmological decade.

When the universe is 10 times older than it is now it will be in the eleventh cosmological decade(100 billion, or 1 with eleven zeros after it). Ten times older than that and it will be in the twelfth.

 #4
avatar+330 
+8

Unlike a standard decade that has a constant value the cosmological decade does not. The cosmological decade scale is base 10 logarithmic. Each successive cosmological decade represents an increase in the total age of the universe by 10 times.

 

The two most common forms of expressing a cosmological decade are:

in Log (seconds per decade) or Log (years per decade)

 

Time zero is the instant before the big bang and the first time unit is Planck time, defined as the epoch

 

 

$$\ CD (-43.2683) = 10^{-43.2683} \; \text{(Time in seconds).}$$

 

There are an infinite number of cosmological decades between the Big Bang and the Planck epoch or any other point in time. The reason for this is there is not a Log value for zero – This is undefined.

 

To convert to years per decade, simply divide the seconds by seconds per year.

The current epoch is CÐ (17.6355) seconds. The log of seconds in a year (7.4991116)

CÐ (17.6355 - 7.4991116) , or CÐ (10.1364) years.

 

The fractional portion of the current CÐ equal to a year is:

 

$$\ \frac {1} {10^{10.1364}}\; = \; 7.30466E-11$$

 

The fractional portion of the current CÐ equal to 2015 years is

 

$$\ \frac {7.30466E-11}{2015} = 1.47188899E-7$$

 

 

To place these values in a more comprehensible perspective if the universe is 24 hours old then 150 years is a millisecond. The normal length of an eye blink is 300-400 milliseconds. it will take you about 52,500 years to blink, on this time scale.

 

Does this answer your question Адриiан Арсовки?

 

 

~D~

 Jan 1, 2015
 #5
avatar+118673 
+8

It is great to see you back on the forum David. 

I thought you must have been incorporated as one with the cosmos :)))))

 Jan 1, 2015
 #6
avatar+129852 
+8

I'll second Melody's opinion.....good to see you back, DavidQD.....now....I figure it may take me a "Cosmological Decade" - at least - to wrap my mind around your answer....LOL !!!

 

As rosala might say...."That made my head hurt."

 

 Jan 1, 2015
 #7
avatar+360 
+5

Everyone pays no attention to MY answer :P

 #8
avatar+360 
+5

Just because my answer isn't as mind boggling doesn't mean I dont deserve a Thumbs Up

 #9
avatar+129852 
0

Sorry, NotTheBestMathMaster.....I didn't mean to neglect you.......you now have some "thumbs-up" and points from me....!!!

 

 Jan 1, 2015
 #10
avatar+330 
+8

HI Melody and CPhill !!!

 

It seems I’ve been gone for a cosmic fortnight -- not quite as long as a decade but longer than an imperial minim …

 Jan 1, 2015
 #11
avatar+330 
+8

Now that I think about it . . . I’ve been gone less than a “blink

 

Happy new year everyone!

 Jan 1, 2015
 #12
avatar+129852 
+8

Happy New Year, DavidQD.....!!!

 

 Jan 1, 2015
 #13
avatar+118673 
+8
Best Answer

Happy New Year DavidQD

Happy New year CPhill

and

Happy New Year NotTheBestMathMaster   :)

 

 

 

 

 


  

 

        

Melody Jan 1, 2015
 #14
avatar+360 
0

Lol ty it was more of a joke from me, but ty anyway xD


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