+33653 If we assume the density of asphalt is about 2000kg/m3, and 1 ton = 907kg then
volume = 907/2000 m3
For a thickness of 166mm (=0.166m) the area covered is
$${\mathtt{area}} = {\frac{{\mathtt{907}}}{\left({\mathtt{2\,000}}{\mathtt{\,\times\,}}{\mathtt{0.166}}\right)}} \Rightarrow {\mathtt{area}} = {\mathtt{2.731\: \!927\: \!710\: \!843\: \!373\: \!5}}$$
or area ≈ 2.7 m2
+33653 If we assume the density of asphalt is about 2000kg/m3, and 1 ton = 907kg then
volume = 907/2000 m3
For a thickness of 166mm (=0.166m) the area covered is
$${\mathtt{area}} = {\frac{{\mathtt{907}}}{\left({\mathtt{2\,000}}{\mathtt{\,\times\,}}{\mathtt{0.166}}\right)}} \Rightarrow {\mathtt{area}} = {\mathtt{2.731\: \!927\: \!710\: \!843\: \!373\: \!5}}$$
or area ≈ 2.7 m2
