One way of looking at this problem is to find the total number of ways that you can arrange the letters {b, c, d, e, f, g}; then attach the letter 'a' to each of these arrangements.
There will be 6 choices for the first letter (any of b, c, d, e, f, or g) and then 5 choices for the second letter, 4 choices for the third letter, 3 choices for the fourth letter, 2 choices for the fifth letter, and only one choice for the last letter: 6 x 5 x 4 x 3 x 2 x 1 = 6!.
One way of looking at this problem is to find the total number of ways that you can arrange the letters {b, c, d, e, f, g}; then attach the letter 'a' to each of these arrangements.
There will be 6 choices for the first letter (any of b, c, d, e, f, or g) and then 5 choices for the second letter, 4 choices for the third letter, 3 choices for the fourth letter, 2 choices for the fifth letter, and only one choice for the last letter: 6 x 5 x 4 x 3 x 2 x 1 = 6!.