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How many real numbers are not in the domain of the function

 

 

f (x) = 1/(x-64) + 1/(x^2-64) + 1/(x^3-64)

 Jan 28, 2019

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 #1
avatar+532 
+2

this means that either x-64, x^2-64, or x^3-64 is 0. so x can be 64, 8, -8, or 4 for a total of 4 solutions.

 Jan 28, 2019
 #1
avatar+532 
+2
Best Answer

this means that either x-64, x^2-64, or x^3-64 is 0. so x can be 64, 8, -8, or 4 for a total of 4 solutions.

asdf335 Jan 28, 2019

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