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0
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How many real solutions does the function below have? Explain how you know.

 

y = 3x^2+6x+2

 Apr 26, 2021
 #1
avatar+389 
+2

none(if y=0) since we use the quadratic equation and we use a calculator we got our answer :D

 Apr 27, 2021
 #2
avatar+2252 
+1

I think there are actually 2. 

 

You can tell from the discriminant, b^2 - 4ac

If b^2 - 4ac = 0, then there's 1. 

If b^2 - 4ac > 0, then there are 2. 

If b^2 - 4ac < 0, then there are 0. 

 

=^._.^=

catmg  Apr 27, 2021

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