+128 How many real solutions does this equation have... log6=log(4x - x^2)
A. 0
B. 1
C. 2
D. 3
E. none of these
+129840 log6=log(4x - x^2) we need to solve this :
6 = 4x - x^2 rearrange as
x^2 - 4x - 6 = 0 .... this will not factor......the [potential] solutions are :
x = 2 + √10 ≈ 5.1623 ... or x = 2 - √10 ≈ -1.1623
However......both [potential] solutions produce a negative log on the right......so.....there are no real solutions to this
