How many terms are there in a geometric series if the first term is 5, the common ratio is 3, and the sum of the series is 65?
n=3
n=4
n=5
n=6
Sum of a geometric series is given by
First term [ 1 - common ratio^n ] / [ 1 - common ratio]
Where n is the sum of the first n terms
So we have
65 = 5 [ 1 - 3^n ] / [ 1 - 3 ] simplify
65 = 5 [ 1 - 3^n ] / -2 multiply by -1 on top/bottom of rthe right side
65 = 5 [ 3^n - 1] / 2 multiply both sides by 2/5
26 = 3^n - 1 add 1 to both sides
27 = 3^n
Because 3^3 = 27......then n = 3 terms