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+1
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thank you

Guest Nov 6, 2017
 #1
avatar+7089 
+1

1 * 1012  =  n( 4 * 104)

 

We want to solve this for  n . That is the number of times  1 * 1012  is greater than  4 * 104

Divide both sides of the equation by  4 * 104 .

 

\(\frac{1*10^{12}}{4*10^4}\)  =  n

                                         Reduce the fraction by  104 .

\(\frac{1*10^{8}}{4}\)  =  n

 

\(\frac{10^{8}}{4}\)  =  n

 

\(\frac{1}{4}\) * 108  =  n

 

0.25 * 108  =  n

 

n  =  25 000 000

hectictar  Nov 6, 2017
edited by hectictar  Nov 6, 2017
 #2
avatar+86889 
+2

Note....we can write 1 x 10^12   as   10  x 10^11

 

So we have

 

[ 10  x 10^11 ] / [ 4 x 10^4 ]  =

 

[ 10 / 4 ]  *  [ 10^11  /  10^4 ]  =

 

2.5  *  10^7  =

 

25,000,000     times greater

 

 

cool cool cool

CPhill  Nov 6, 2017

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