How much energy is required to heat 3 kg of water of this example :Heat 3 kg of ice from –10°C to 0°C
Q=mcΔT m= mass c= specific heat ΔT = c
The Specific Heat of Water as ice is 2.03 J/g
3000g x 2.03 x 10 degrees = 60,900 J J= joules
+37146 
