​ How much greater is the average rate of change over the interval [9, 10] than the interval [5, 8] ?

average rate of change over the interval  [9, 10]   =   \(\frac{f(10)-f(9)}{10-9}\ =\ \frac{11014-4052}{1}\ =\ \frac{6962}{1}\ =\ 6962\)

average rate of change over the interval  [5,  8]   =  \(\frac{f(8)-f(5)}{8-5}\ =\ \frac{1491-75}{8-5}\ =\ \frac{1416}{3}\ =\ 472\)

How much greater is the average rate of change over the interval [9, 10] than the interval [5, 8]  ?

In other words...

How much greater is  6962  than  472  ?

6490  seems to be correct 

is it 6490?????