We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
207
1
avatar

Tickets to a baseball game cost $20 for the nosebleeds and $45 for the mezzanine level. If the total revenue was $717,500 and 21,500 tickets were sold across the two sections, how much more did the stadium make on mezzanine ticket sales than nosebleed ticket sales?

 Apr 29, 2019
 #1
avatar+104882 
+1

Let the number of nosebleed tickets sold  = T.....the the number of mezzanine tickets sold  = (21500 - T)

 

So

 

Number of nosebleed tickets sold * price each + number of mezz tickets sold * price each = revenue

 

T(20)  + ( 21500 - T)(45)  =  717500      simplify

 

20T + 967500 - 45T  =  717500

 

-25T + 967500 = 717500       subtract  967500 from each side

 

-25T  = -250000     divide both sides by -25

 

T = 10000  = nosebleed tickets sold   and    21500 - 10000  = 11500 mezz sold

 

So.....

 

Revenue from mezz =  45(11500)   =  $ 517500

Revenue from nosebleed  =  717500 - 517500  = $ 200000

 

So....they made   517500 - 200000  = $317500  more from mezz sales than nosebleed sales

 

 

 

 

cool cool cool

 Apr 29, 2019

6 Online Users