Jane needs to make 10 liters of a solution that is 10% salt. She has a solution that is 5% salt and a solution that is 25% salt. How much of each solution should Mia use?
Select one:
a. 4 liters of the 5% salt solution and 6 liters of the 25% salt solution
b. 2.5 liters of the 5% salt solution and 7.5 liters of the 25% salt solution
c. 7.5 liters of the 5% salt solution and 2.5 liters of the 25% salt solution
d. 8 liters of the 5% salt solution and 2 liters of the 25% salt solution
The total salt in the final solution has to equal the salt from the component solutions
x = liters of 25% salt content = .25x
10-x = liters of 5 % salt content = .05(10-x)
final solution salt content = .1 (10) = 1
.25x+ .05(10-x) = 1
.25x + .5 - .05x = 1
.20x = .5
x = 2.5 liters of 25% and 10 -2.5 = 7.5 liters of 5 %
Let the no. of liters of 5% solution= x
So...the no. of liters of 25% solution is (10 - x)
So.....we have this
5 % solution * amt + 25% solution * amt = 10% solution * 10 liters
.05 x + .25(10 - x) = .10 * 10 simplify
05x + 2.5 - .25x + 1
-.20x + 2.5 = 1 subtract 2.5 from both sides
-.20x = - 1.5 divide both sides by .20
x = 7.5 liters of 5% solution
And
10 - x = 10 - 7.5 = 2.5 liters of 25% solution
Answer " C "