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How should I calculate (95!/92!*5!)? 

 Feb 20, 2020
 #1
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+1

                                            95 * 94 * 93 * 92  * 91  * 90 * .....

  (95!)/(92!) =                     ____________________________  =       95 * 94 * 93

                                                                 92  *  91  *  90  *......

 

 

And  5!   =120

 

So  just calculate

 

95 * 94 * 93  * 120

 

 

cool cool cool

 Feb 20, 2020
edited by CPhill  Feb 20, 2020
 #2
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So if you want to do a! - d! you should basically do a! * b! * c! ? Sorry I'm kind of confused

Guest Feb 20, 2020
 #3
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+1

 

I believe Chris is telling you that the important thing to understand here is that when you have one factorial divided by another factorial, you can reduce your multiplications significantly by using cancellation.

Guest Feb 20, 2020

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