How should I calculate (95!/92!*5!)?
95 * 94 * 93 * 92 * 91 * 90 * .....
(95!)/(92!) = ____________________________ = 95 * 94 * 93
92 * 91 * 90 *......
And 5! =120
So just calculate
95 * 94 * 93 * 120
So if you want to do a! - d! you should basically do a! * b! * c! ? Sorry I'm kind of confused
I believe Chris is telling you that the important thing to understand here is that when you have one factorial divided by another factorial, you can reduce your multiplications significantly by using cancellation.
+128408 
