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# How should I isolate y in this function?

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Here's the function: $$4 - y = {\sqrt{3x}}$$

I keep on getting $$y = {-\sqrt{3x}} + 13$$, which I know is wrong when I compared the two functions graphically.

Guest Oct 15, 2018

#1
+93866
+3

HUH?

$$4 - y = {\sqrt{3x}}\\ 4 = {\sqrt{3x}}+y\\ 4 - {\sqrt{3x}}=y\\ y=4 - {\sqrt{3x}}$$

Melody  Oct 15, 2018
#1
+93866
+3

HUH?

$$4 - y = {\sqrt{3x}}\\ 4 = {\sqrt{3x}}+y\\ 4 - {\sqrt{3x}}=y\\ y=4 - {\sqrt{3x}}$$

Melody  Oct 15, 2018