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How to calculate ( 1/a - 2/b ) / ( 2/a - 1/b )

 Aug 20, 2015

Best Answer 

 #3
avatar+26367 
+5

How to calculate ( 1/a - 2/b ) / ( 2/a - 1/b )

$$\dfrac{ ( \frac{1}{a} - \frac{2}{b} ) } { ( \frac{2}{a} - \frac{1}{b} ) }\cdot \left( \dfrac{ab}{ab} \right) \\\\\\
=
\dfrac{ ( \frac{1}{a} - \frac{2}{b} ) \cdot ab} { ( \frac{2}{a} - \frac{1}{b} ) \cdot ab }\\\\\\
=
\dfrac{ ( \frac{1}{a}\cdot ab - \frac{2}{b}\cdot ab ) } { ( \frac{2}{a}\cdot ab - \frac{1}{b}\cdot ab ) }\\\\\\
=
\dfrac{ ( b- 2a) } { (2b - a) }\\\\\\$$

 

 Aug 21, 2015
 #1
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0

p-4/p + 16/5p - 1/5 =?

 Aug 20, 2015
 #2
avatar+10 
+5

Get the LCM of a and b which is ab then divide accordingly. You should get ((b-2a)/ab) / ((2b-a)/ab) then after cancelling ab on both sides, you remain with (b-2a) / (2b-a)

 Aug 20, 2015
 #3
avatar+26367 
+5
Best Answer

How to calculate ( 1/a - 2/b ) / ( 2/a - 1/b )

$$\dfrac{ ( \frac{1}{a} - \frac{2}{b} ) } { ( \frac{2}{a} - \frac{1}{b} ) }\cdot \left( \dfrac{ab}{ab} \right) \\\\\\
=
\dfrac{ ( \frac{1}{a} - \frac{2}{b} ) \cdot ab} { ( \frac{2}{a} - \frac{1}{b} ) \cdot ab }\\\\\\
=
\dfrac{ ( \frac{1}{a}\cdot ab - \frac{2}{b}\cdot ab ) } { ( \frac{2}{a}\cdot ab - \frac{1}{b}\cdot ab ) }\\\\\\
=
\dfrac{ ( b- 2a) } { (2b - a) }\\\\\\$$

 

heureka Aug 21, 2015

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