How to calculate ( 1/a - 2/b ) / ( 2/a - 1/b )
(1a−2b)(2a−1b)⋅(abab)=(1a−2b)⋅ab(2a−1b)⋅ab=(1a⋅ab−2b⋅ab)(2a⋅ab−1b⋅ab)=(b−2a)(2b−a)
p-4/p + 16/5p - 1/5 =?
Get the LCM of a and b which is ab then divide accordingly. You should get ((b-2a)/ab) / ((2b-a)/ab) then after cancelling ab on both sides, you remain with (b-2a) / (2b-a)