how to calculate integral?

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Guest Jul 31, 2014

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Best Answer

That depends which integral.

I'll do a very simple one for you.

$$\int 5x^6+\frac{9}{2}x^3 +4 \;dx\\\\
=\frac{5x^{6+1}}{7}+\frac{9x^{3+1}}{2\times4}+4x+c\\\\
=\frac{5x^{7}}{7}+\frac{9x^{4}}{8}+4x+c\\\\$$

Melody Jul 31, 2014

Melody · Answer 1 · 2014-07-31T12:06:33

That depends which integral.

I'll do a very simple one for you.

$$\int 5x^6+\frac{9}{2}x^3 +4 \;dx\\\\
=\frac{5x^{6+1}}{7}+\frac{9x^{3+1}}{2\times4}+4x+c\\\\
=\frac{5x^{7}}{7}+\frac{9x^{4}}{8}+4x+c\\\\$$