How to calculate the sin of 73°18'42''...?
\(73°18'42''= 73° + 18'\times \frac{1°}{60'}+42'' \times\frac{1°}{3600''}\)
\(=73.3116\overline{6}°\)
\(sin 73°18'42'' = sin 73.3116\overline{6}°\)
\({\color{blue}=0.957880987839}\)
!
Start from right to left:
42 seconds/60 =0.7 minutes
0.7 + 18 minutes =18.7 minutes
18.7 / 60 =0.31167 degrees.
0.31167 + 73 degrees =73.31167 degrees. Use this number and take its sin, cos, tan.....etc.
Sin(73.31167) =~ 0.957881
